-30x^2+250x=490-30x

Solution for -30x^2+250x=490-30x equation:

-30x^2+250x=490-30x

We move all terms to the left:

-30x^2+250x-(490-30x)=0

We add all the numbers together, and all the variables

-30x^2+250x-(-30x+490)=0

We get rid of parentheses

-30x^2+250x+30x-490=0

We add all the numbers together, and all the variables

-30x^2+280x-490=0

a = -30; b = 280; c = -490;
Δ = b2-4ac
Δ = 2802-4·(-30)·(-490)
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{19600}=140$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(280)-140}{2*-30}=\frac{-420}{-60}
=+7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(280)+140}{2*-30}=\frac{-140}{-60}
=2+1/3
$